In this article, you will learn How to Compare two Strings in Java? String is a succession of characters. In Java, objects of String are permanent which implies they are steady and can’t be changed once made. The following are 5 methods for contrasting two Strings in Java: Attention peruser! Try not to quit adapting now. Get hold of all the significant Java Foundation and Collections ideas with the Fundamentals of Java and Java Collections Course at an understudy cordial cost and become industry prepared. To finish your readiness from learning a language to DS Algo and some more.
Utilizing client characterized work: Define a capacity to contrast esteems and following conditions :
- if (string1 > string2) it returns a positive worth.
- if both the strings are equivalent lexicographically
- i.e.(string1 == string2) it brings 0 back.
- if (string1 < string2) it returns a negative worth.
- The worth is determined as (int)str1.charAt(i) – (int)str2.charAt(i)
Examples:
Input 1: GeeksforGeeks Input 2: Practice Output: -9 Input 1: Geeks Input 2: Geeks Output: 0 Input 1: GeeksforGeeks Input 2: Geeks Output: 8
Program:
// Java program to Compare two strings // lexicographically public class GFG { // This method compares two strings // lexicographically without using // library functions public static int stringCompare(String str1, String str2) { int l1 = str1.length(); int l2 = str2.length(); int lmin = Math.min(l1, l2); for ( int i = 0 ; i < lmin; i++) { int str1_ch = ( int )str1.charAt(i); int str2_ch = ( int )str2.charAt(i); if (str1_ch != str2_ch) { return str1_ch - str2_ch; } } // Edge case for strings like // String 1="Geeks" and String 2="Geeksforgeeks" if (l1 != l2) { return l1 - l2; } // If none of the above conditions is true, // it implies both the strings are equal else { return 0 ; } } // Driver function to test the above program public static void main(String args[]) { String string1 = new String( "Geeksforgeeks" ); String string2 = new String( "Practice" ); String string3 = new String( "Geeks" ); String string4 = new String( "Geeks" ); // Comparing for String 1 < String 2 System.out.println( "Comparing " + string1 + " and " + string2 + " : " + stringCompare(string1, string2)); // Comparing for String 3 = String 4 System.out.println( "Comparing " + string3 + " and " + string4 + " : " + stringCompare(string3, string4)); // Comparing for String 1 > String 4 System.out.println( "Comparing " + string1 + " and " + string4 + " : " + stringCompare(string1, string4)); } } |
Output:
Comparing Geeksforgeeks and Practice : -9 Comparing Geeks and Geeks : 0 Comparing Geeksforgeeks and Geeks : 8
Using String.equals() :In Java, string equals() method compares the two given strings based on the data/content of the string. If all the contents of both the strings are same then it returns true. If any character does not match, then it returns false.
Syntax:
str1.equals(str2);
Here str1 and str2 both are the strings which are to be compared.
Examples:
Input 1: GeeksforGeeks Input 2: Practice Output: false Input 1: Geeks Input 2: Geeks Output: true Input 1: geeks Input 2: Geeks Output: false
Program:
// Java program to Compare two strings // lexicographically public class GFG { public static void main(String args[]) { String string1 = new String( "Geeksforgeeks" ); String string2 = new String( "Practice" ); String string3 = new String( "Geeks" ); String string4 = new String( "Geeks" ); String string5 = new String( "geeks" ); // Comparing for String 1 != String 2 System.out.println( "Comparing " + string1 + " and " + string2 + " : " + string1.equals(string2)); // Comparing for String 3 = String 4 System.out.println( "Comparing " + string3 + " and " + string4 + " : " + string3.equals(string4)); // Comparing for String 4 != String 5 System.out.println( "Comparing " + string4 + " and " + string5 + " : " + string4.equals(string5)); // Comparing for String 1 != String 4 System.out.println( "Comparing " + string1 + " and " + string4 + " : " + string1.equals(string4)); } } |
Output:
Comparing Geeksforgeeks and Practice : false Comparing Geeks and Geeks : true Comparing Geeks and geeks : false Comparing Geeksforgeeks and Geeks : false
Using String.equalsIgnoreCase() : The String.equalsIgnoreCase() method compares two strings irrespective of the case (lower or upper) of the string. This method returns true if the argument is not null and the contents of both the Strings are same ignoring case, else false.
Syntax:
str2.equalsIgnoreCase(str1);
Here str1 and str2 both are the strings which are to be compared.
Examples:
Input 1: GeeksforGeeks Input 2: Practice Output: false Input 1: Geeks Input 2: Geeks Output: true Input 1: geeks Input 2: Geeks Output: true
Program:
// Java program to Compare two strings // lexicographically public class GFG { public static void main(String args[]) { String string1 = new String( "Geeksforgeeks" ); String string2 = new String( "Practice" ); String string3 = new String( "Geeks" ); String string4 = new String( "Geeks" ); String string5 = new String( "geeks" ); // Comparing for String 1 != String 2 System.out.println( "Comparing " + string1 + " and " + string2 + " : " + string1.equalsIgnoreCase(string2)); // Comparing for String 3 = String 4 System.out.println( "Comparing " + string3 + " and " + string4 + " : " + string3.equalsIgnoreCase(string4)); // Comparing for String 4 = String 5 System.out.println( "Comparing " + string4 + " and " + string5 + " : " + string4.equalsIgnoreCase(string5)); // Comparing for String 1 != String 4 System.out.println( "Comparing " + string1 + " and " + string4 + " : " + string1.equalsIgnoreCase(string4)); } } |
Output:
Comparing Geeksforgeeks and Practice : false Comparing Geeks and Geeks : true Comparing Geeks and geeks : true Comparing Geeksforgeeks and Geeks : false
Using Objects.equals() : Object.equals(Object a, Object b) method returns true if the arguments are equal to each other and false otherwise. Consequently, if both arguments are null, true is returned and if exactly one argument is null, false is returned. Otherwise, equality is determined by using the equals() method of the first argument.
Syntax:
public static boolean equals(Object a, Object b)
Here a and b both are the string objects which are to be compared.
Examples:
Input 1: GeeksforGeeks Input 2: Practice Output: false Input 1: Geeks Input 2: Geeks Output: true Input 1: null Input 2: null Output: true
Program:
// Java program to Compare two strings // lexicographically import java.util.*; public class GFG { public static void main(String args[]) { String string1 = new String( "Geeksforgeeks" ); String string2 = new String( "Geeks" ); String string3 = new String( "Geeks" ); String string4 = null ; String string5 = null ; // Comparing for String 1 != String 2 System.out.println( "Comparing " + string1 + " and " + string2 + " : " + Objects.equals(string1, string2)); // Comparing for String 2 = String 3 System.out.println( "Comparing " + string2 + " and " + string3 + " : " + Objects.equals(string2, string3)); // Comparing for String 1 != String 4 System.out.println( "Comparing " + string1 + " and " + string4 + " : " + Objects.equals(string1, string4)); // Comparing for String 4 = String 5 System.out.println( "Comparing " + string4 + " and " + string5 + " : " + Objects.equals(string4, string5)); } } |
Output:
Comparing Geeksforgeeks and Geeks : false Comparing Geeks and Geeks : true Comparing Geeksforgeeks and null : false Comparing null and null : true
Using String.compareTo() :
Syntax:
int str1.compareTo(String str2)
Working:
It compares and returns the following values as follows:
- if (string1 > string2) it returns a positive value.
- if both the strings are equal lexicographically
i.e.(string1 == string2) it returns 0. - if (string1 < string2) it returns a negative value.
Examples:
Input 1: GeeksforGeeks Input 2: Practice Output: -9 Input 1: Geeks Input 2: Geeks Output: 0 Input 1: GeeksforGeeks Input 2: Geeks Output: 8
Program:
// Java program to Compare two strings // lexicographically import java.util.*; public class GFG { public static void main(String args[]) { String string1 = new String( "Geeksforgeeks" ); String string2 = new String( "Practice" ); String string3 = new String( "Geeks" ); String string4 = new String( "Geeks" ); // Comparing for String 1 < String 2 System.out.println( "Comparing " + string1 + " and " + string2 + " : " + string1.compareTo(string2)); // Comparing for String 3 = String 4 System.out.println( "Comparing " + string3 + " and " + string4 + " : " + string3.compareTo(string4)); // Comparing for String 1 > String 4 System.out.println( "Comparing " + string1 + " and " + string4 + " : " + string1.compareTo(string4)); } } |
Output:
Comparing Geeksforgeeks and Practice : -9 Comparing Geeks and Geeks : 0 Comparing Geeksforgeeks and Geeks : 8
Why not use == for comparison of Strings?
In general both equals() and “==” operators in Java are used to compare objects to check equality but here are some of the differences between the two:
- Main difference between .equals() method and == operator is that one is method and other is operator.
One can use == operators for reference comparison (address comparison) and .equals() method for content comparison.
In simple words, == checks if both objects point to the same memory location whereas .equals() evaluates to the comparison of values in the objects.
Example:
// Java program to understand // why to avoid == operator public class Test { public static void main(String[] args) { String s1 = new String( "HELLO" ); String s2 = new String( "HELLO" ); System.out.println(s1 == s2); System.out.println(s1.equals(s2)); } } |
Output:
false true
Explanation: Here two String objects are being created namely s1 and s2.
-
- Both s1 and s2 refer to different objects.
- When one uses == operator for s1 and s2 comparison then the result is false as both have different addresses in memory.
- Using equals, the result is true because its only compares the values given in s1 and s2
Also Read: How to implement recursion in C++?